4x^2-52x=-168

Solution for 4x^2-52x=-168 equation:

4x^2-52x=-168

We move all terms to the left:

4x^2-52x-(-168)=0

We add all the numbers together, and all the variables

4x^2-52x+168=0

a = 4; b = -52; c = +168;
Δ = b2-4ac
Δ = -522-4·4·168
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-4}{2*4}=\frac{48}{8}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+4}{2*4}=\frac{56}{8}
=7
$